NOT from a NAND with tied inputs — NOT gate
coreone gate, both inputs shorted
Answer
1 NAND gate realising A′
Why this example is worth doing
Tie both inputs of a NAND together and it inverts, because A·A = A by idempotence and the output bubble does the rest. This is step one of every NAND-only conversion and the reason NAND is universal at all. The page shows the idempotent law doing the work explicitly, since students often assume tying inputs is a special electrical rule rather than an algebraic consequence.
Try your own input in the NOT gate. Truth table, symbol and algebraic form for the inverter, Ā.
How the answer is reached
Gate list
| Node | Gate | Inputs |
|---|---|---|
| g1 | nand | A, A |
NAND-only realisation
A ↑ AA′— 1 NAND gates, verified by reading the network back out.
Truth table
| # | A | A ↑ A |
|---|---|---|
| 0 | 0 | 1 |
| 1 | 1 | 0 |