2:1 mux, S = 0 — multiplexers and decoders
introthe selector equation
Answer
Y = 1
Why this example is worth doing
With the select line low the mux passes its first input. The expression S̄·I₀ + S·I₁ is worth reading as a pattern rather than a formula: each data input is ANDed with the select condition that chooses it, and the results are ORed. Every larger mux and every decoder on this page is that pattern repeated, which is why the page starts with the smallest possible case.
Try your own input in the Multiplexers & decoders. Multiplexers from 2:1 to 16:1 and decoders from 2:4 to 4:16, with the selection logic derived.
How the answer is reached
The probed row
S = 0, I0 = 1, I1 = 0
Output table
| S | I0 | I1 | Y |
|---|---|---|---|
| 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |